((x^2-x-2)/(x^2+5x+6))((x+1)(4x+8))

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Solution for ((x^2-x-2)/(x^2+5x+6))((x+1)(4x+8)) equation: 


D( x )

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

x in (-oo:-3) U (-3:-2) U (-2:+oo)

((x^2-x-2)/(x^2+5*x+6))*(x+1)*(4*x+8) = 0

((x^2-x-2)*(x+1)*(4*x+8))/(x^2+5*x+6) = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

(x+1)*(x-2) = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

(x+3)*(x+2) = 0

((x+1)^2*(x-2)*(4*x+8))/((x+3)*(x+2)) = 0

( 4*x+8 )

4*x+8 = 0 // - 8

4*x = -8 // : 4

x = -8/4

x = -2

( x+1 )

x+1 = 0 // - 1

x = -1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -2} 

x in { -1, -1, 2 }

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